- Commit
- 88accd95a78f22a9730a9353217666e3bf6d0e00
- Parent
- 19a49a960531305f90baf123811ae6465d5499fb
- Author
- Pablo <pablo-escobar@riseup.net>
- Date
Tweaked some sentences
Source code for my notes on representations of semisimple Lie algebras and Olivier Mathieu's classification of simple weight modules
Tweaked some sentences
1 file changed, 17 insertions, 15 deletions
Status | File Name | N° Changes | Insertions | Deletions |
Modified | sections/semisimple-algebras.tex | 32 | 17 | 15 |
diff --git a/sections/semisimple-algebras.tex b/sections/semisimple-algebras.tex @@ -697,19 +697,21 @@ The ``existence'' part is more nuanced. Our first instinct is, of course, to try to generalize the proof used for \(\mathfrak{sl}_3(K)\). The issue is that our proof relied heavily on our knowledge of the roots of \(\mathfrak{sl}_3(K)\). This is therefore little hope of generalizing this -argument to some arbitrary \(\mathfrak{g}\) with out current knowledge. Instead, -we focus on a simpler question: how can we construct \emph{any} highest -\(\mathfrak{g}\)-module \(M\) of highest weight \(\lambda\)? - -If \(M\) is a finite-dimensional module with highest weight vector \(m^+ \in -M_\lambda\), we already know \(H \cdot m^+ = \lambda(H) m^+\) for all -\(\mathfrak{h}\) and \(X \cdot m^+ = 0\) for \(X \in \mathfrak{g}_\alpha\), -\(\alpha \in \Delta^+\). In other words, the restriction of \(M\) to the Borel -subalgebra \(\mathfrak{b} \subset \mathfrak{g}\) has a prescribed action. On the -other hand, we have essentially no information about the action of the rest of -\(\mathfrak{g}\) on \(M\). Nevertheless, given a \(\mathfrak{b}\)-module we may -obtain a \(\mathfrak{g}\)-module by formally extending the action of -\(\mathfrak{b}\) via induction. This leads us to the following definition. +argument to some arbitrary \(\mathfrak{g}\) with out current knowledge. +Instead, we focus on a simpler question: how can we construct \emph{any} +(potentially infinite-dimensional) \(\mathfrak{g}\)-module \(M\) of highest +weight \(\lambda\)? + +If \(M\) is a module with highest weight vector \(m^+ \in M_\lambda\), we +already know \(H \cdot m^+ = \lambda(H) m^+\) for all \(\mathfrak{h}\) and \(X +\cdot m^+ = 0\) for \(X \in \mathfrak{g}_\alpha\), \(\alpha \in \Delta^+\). +Since \(M = \mathcal{U}(\mathfrak{g}) \cdot m^+\), this implies the restriction +of \(M\) to the Borel subalgebra \(\mathfrak{b} \subset \mathfrak{g}\) has a +prescribed action. On the other hand, we have essentially no information about +the action of the rest of \(\mathfrak{g}\) on \(M\). Nevertheless, given a +\(\mathfrak{b}\)-module we may obtain a \(\mathfrak{g}\)-module by formally +extending the action of \(\mathfrak{b}\) via induction. This leads us to the +following definition. \begin{definition}\label{def:verma}\index{\(\mathfrak{g}\)-module!(generalized) Verma modules} The \(\mathfrak{g}\)-module \(M(\lambda) = @@ -720,8 +722,8 @@ obtain a \(\mathfrak{g}\)-module by formally extending the action of module of weight \(\lambda\)}. \end{definition} -It turns out that \(M(\lambda)\) enjoys many of the features we've grown used to -in the past chapters. Explicitly\dots +It turns out that \(M(\lambda)\) enjoys many of the features we've grown used +to in the past chapters. Explicitly\dots \begin{proposition}\label{thm:verma-is-weight-mod} The weight spaces decomposition