- Commit
- cafddd125eb9bb578ba4fc32e2d3f0157dc8546a
- Parent
- 70c1543f6727e7fc7768e91cfedad0120096abb2
- Author
- Pablo <pablo-escobar@riseup.net>
- Date
Fixed multiple typos in the second sections
Riemannian Geometry course project on the manifold H¹(I, M) of class H¹ curves on a Riemannian manifold M and its applications to the geodesics problem
Fixed multiple typos in the second sections
1 file changed, 40 insertions, 39 deletions
Status | File Name | N° Changes | Insertions | Deletions |
Modified | sections/structure.tex | 79 | 40 | 39 |
diff --git a/sections/structure.tex b/sections/structure.tex @@ -10,7 +10,7 @@ Given an interval \(I\), recall that a continuous curve \(\gamma : I \to \RR^n\) is called \emph{a class \(H^1\)} curve if \(\gamma\) is absolutely continuous, \(\dot \gamma(t)\) exists for almost all \(t \in I\) and \(\dot\gamma \in H^0(I, \RR^n) = L^2(I, \RR^n)\). It is a well known fact that -the so called \emph{Sobolev space \(H^1(I, \RR^n)\)} of all class \(H^1\) +the so called \emph{Sobolev space \(H^1([0, 1], \RR^n)\)} of all class \(H^1\) curves in \(\RR^n\) is a Hilbert space under the inner product given by \[ \langle \gamma, \eta \rangle_1 @@ -47,8 +47,8 @@ described in section~\ref{sec:introduction}, we would like \({C'}^\infty(I, \RR^n)\) to be a Banach manifold under which both the energy functional and the length functional are smooth maps. As most function spaces, \({C'}^\infty(I, \RR^n)\) admits several natural topologies. Some of the most obvious candidates -are the uniform topology and the topology of \(H^0\) norm, which are the -topologies induces by the norms +are the uniform topology and the topology of the \(\norm\cdot_0\) norm, which +are the topologies induces by the norms \begin{align*} \norm{\gamma}_\infty & = \sup_t \norm{\gamma(t)} \\ \norm{\gamma}_0 & = \int_0^1 \norm{\gamma(t)}^2 \; \dt @@ -91,20 +91,21 @@ approach \(\ell(\gamma) = \sqrt 2\) as \(n\) approaches \(\infty\). The issue with this particular example is that while \(\gamma_n \to \gamma\) uniformly, \(\dot\gamma_n\) does not converge to \(\dot\gamma\) in the uniform -topology. This hints at the fact that in order to \(E\) and \(\ell\) to be +topology. This hints at the fact that in order for \(E\) and \(\ell\) to be continuous maps we need to control both \(\gamma\) and \(\dot\gamma\). Hence a natural candidate for a norm in \({C'}^\infty(I, \RR^n)\) is \[ \norm{\gamma}_1^2 = \norm{\gamma}_0^2 + \norm{\dot\gamma}_0^2, \] which is, of course, the norm induced by the inner product \(\langle \, , -\rangle_1\) -- here \(\norm{\cdot}_0\) denote the norm of \(H^0(I, \RR^n)\). +\rangle_1\) -- here \(\norm{\cdot}_0\) denote the norm of \(H^0(I, \RR^n) = +L^2(I, \RR^n)\). The other issue we face is one of completeness. Since \(\RR^n\) has a global chart, we expect \({C'}^\infty(I, \RR^n)\) to be affine too. In other words, it is natural to expect \({C'}^\infty(I, \RR^n)\) to be Banach space. In particular, \({C'}^\infty(I, \RR^n)\) must be complete. This is unfortunately -not the case for \({C'}^\infty(I, \RR^n)\) the norm \(\norm\cdot_1\), but we +not the case for \({C'}^\infty(I, \RR^n)\) in the \(\norm\cdot_1\) norm, but we can consider its completion. Lo and behold, a classical result by Lebesgue establishes that this completion just so happens to coincide with \(H^1(I, \RR^n)\). @@ -125,9 +126,9 @@ of sections of vector bundles over the unit interval \(I\). Explicitly, we find\dots \begin{proposition} - Given an Euclidean bundle \(E \to I\), the space \(C^0(E)\) of all continuous - sections of \(E\) is is the completion of \({C'}^\infty(E)\) under the norm - given by + Given an Euclidean bundle \(E \to I\) -- i.e. a vector bundle endowed with a + Riemannian metric -- the space \(C^0(E)\) of all continuous sections of \(E\) + is the completion of \({C'}^\infty(E)\) under the norm given by \[ \norm{\xi}_\infty = \sup_t \norm{\xi_t} \] @@ -135,7 +136,7 @@ find\dots \begin{proposition}\label{thm:h0-bundle-is-complete} Given an Euclidean bundle \(E \to I\), the space \(H^0(E)\) of all square - integrable sections of \(E\) is is the completion of \({C'}^\infty(E)\) under + integrable sections of \(E\) is the completion of \({C'}^\infty(E)\) under the inner product given by \[ \langle \xi, \eta \rangle_0 = \int_0^1 \langle \xi_t, \eta_t \rangle \; \dt @@ -143,10 +144,9 @@ find\dots \end{proposition} \begin{proposition} - Given an Euclidean bundle \(E \to I\) -- i.e. a vector bundle endowed with a - Riemannian metric -- the space \(H^1(E)\) of all class class \(H^1\) sections - of \(E\) is the completion of the space \({C'}^\infty(E)\) of piece-wise - smooth sections of \(E\) under the inner product given by + Given an Euclidean bundle \(E \to I\), the space \(H^1(E)\) of all class + \(H^1\) sections of \(E\) is the completion of the space \({C'}^\infty(E)\) + of piece-wise smooth sections of \(E\) under the inner product given by \[ \langle \xi, \eta \rangle_1 = \langle \xi, \eta \rangle_0 + @@ -166,9 +166,16 @@ find\dots \end{proposition} \begin{proof} - Fix \(\xi \in H^1(E)\) and \(t_0, t_1 \in I\) with \(\norm{\xi}_0 \ge - \norm{\xi_{t_0}}\) and \(\norm{\xi}_\infty = \norm{\xi_{t_1}}\). - Then + Given \(\xi \in H^0(E)\) we have + \[ + \norm{\xi}_0^2 + = \int_0^1 \norm{\xi_t}^2 \; \dt + \le \int_0^1 \norm{\xi}_\infty \; \dt + = \norm{\xi}_\infty + \] + + Now given \(\xi \in H^1(E)\) fix \(t_0, t_1 \in I\) with \(\norm{\xi}_\infty + = \norm{\xi_{t_1}}\). Then \[ \begin{split} \norm{\xi}_\infty^2 @@ -181,19 +188,11 @@ find\dots \text{(Cauchy-Schwarz)} & \le \norm{\xi_{t_0}}^2 + 2 \int_0^1 \norm{\xi_s} \cdot \norm{\nabla_{\frac\dd{\dd s}} \xi_s} \; \dd s \\ - & \le \norm{\xi}_0^2 + & \le \norm{\xi}_\infty^2 + \norm{\xi}_0^2 + \norm{\nabla_{\frac\dd\dt} \xi}_0^2 \\ & \le 2 \norm{\xi}_1^2 \end{split} \] - - Finally, given \(\xi \in H^0(E)\) we have - \[ - \norm{\xi}_0^2 - = \int_0^1 \norm{\xi_t}^2 \; \dt - \le \int_0^1 \norm{\xi}_\infty \; \dt - = \norm{\xi}_\infty - \] \end{proof} \begin{note} @@ -318,8 +317,8 @@ precisely\dots We would also like to point out that this is a particular case of a more general construction: that of the Banach manifold \(H^1(E)\) of class \(H^1\) sections of a smooth fiber bundle \(E \to I\) -- not necessarily a vector -bundle. Our construction of \(H^1(I, M)\) is equivalent to of of the manifold -\(H^1(I \times M)\) in the sense that the canonical map +bundle. Our construction of \(H^1(I, M)\) is equivalent to that of the manifold +\(H^1(I \times M)\), in the sense that the canonical map \[ \arraycolsep=1pt \begin{array}{rl} @@ -339,7 +338,9 @@ of a vector bundle -- the so called \emph{vector bundle neighborhoods of \(E\)}. This construction is highlighted in great detail and generality in the first section of \cite[ch.~11]{palais}, but unfortunately we cannot afford such a diversion in this short notes. Having said that, we are now finally ready to -discuss the Riemannian structure of \(H^1(I, M)\). +layout the Riemannian structure of \(H^1(I, M)\). + +We are finally ready to discuss some applications. \subsection{The Metric of \(H^1(I, M)\)} @@ -352,13 +353,13 @@ proposition~\ref{thm:tanget-space-topology}. In fact, this isomorphisms may be extended to a canonical isomorphism of vector bundles, as seen in\dots \begin{lemma}\label{thm:alpha-fiber-bundles-definition} - Given \(i = 0, 1\), the collection \(\{(\psi_{i, \gamma}(H^1(U_\gamma) \times + Given \(i = 0, 1\), the collection \(\{(\psi_{i, \gamma}(H^1(W_\gamma) \times H^i(\gamma^* TM)), \psi_{i, \gamma}^{-1})\}_{\gamma \in {C'}^\infty(I, M)}\) with \[ \arraycolsep=1pt \begin{array}{rl} - \psi_{i, \gamma} : H^1(U_\gamma) \times H^i(\gamma^* TM) \to + \psi_{i, \gamma} : H^1(W_\gamma) \times H^i(\gamma^* TM) \to & \coprod_{\eta \in H^1(I, M)} H^i(\eta^* TM) \\ (X, Y) \mapsto & \begin{array}[t]{rl} @@ -384,20 +385,20 @@ extended to a canonical isomorphism of vector bundles, as seen in\dots \end{proposition} \begin{proof} - Note that the sets \(H^1(U_\gamma) \times T_\gamma H^1(I, M)\) are precisely + Note that the sets \(H^1(W_\gamma) \times T_\gamma H^1(I, M)\) are precisely the images of the canonical charts \[ \varphi_\gamma : - \varphi_\gamma^{-1}(H^1(U_\gamma) \times T_\gamma H^1(I, M)) + \varphi_\gamma^{-1}(H^1(W_\gamma) \times T_\gamma H^1(I, M)) \subset T H^1(I, M) - \to H^1(U_\gamma) \times T_\gamma H^1(I, M) + \to H^1(W_\gamma) \times T_\gamma H^1(I, M) \] of \(T H^1(I, M)\). By composing charts we get local vector bundle isomorphism \(\psi_{1, \gamma} \circ (\id, \varphi_\gamma) \circ \varphi_\gamma : - \varphi_\gamma^{-1}(H^1(U_\gamma) \times T_\gamma H^1(I, M)) \isoto \psi_{1, - \gamma}(H^1(U_\gamma) \times H^1(\gamma^* TM))\). Because of the fact that + \varphi_\gamma^{-1}(H^1(W_\gamma) \times T_\gamma H^1(I, M)) \isoto \psi_{1, + \gamma}(H^1(W_\gamma) \times H^1(\gamma^* TM))\). Because of the fact that \(\varphi_\gamma\) and \(\psi_{1, \gamma}^{-1}\) are charts, this isomorphisms agree in the intersections, so they may be glued together into a global vector bundle isomorphism. Furthermore, by construction the @@ -467,7 +468,7 @@ words, we'll show\dots \begin{proposition}\label{thm:partial-is-smooth-sec} The map \begin{align*} - \partial : H^1(I, M) & \to \coprod_{\gamma} H^0\gamma^* TM \\ + \partial : H^1(I, M) & \to \coprod_{\gamma} H^0(\gamma^* TM) \\ \gamma & \mapsto \dot\gamma \end{align*} is a smooth section of \(\coprod_{\gamma \in H^1(I, M)} H^0(\gamma^* TM) \to @@ -482,8 +483,8 @@ words, we'll show\dots \begin{align*} \mathfrak{X}(H^1(I, M)) & \to \Gamma\left(\coprod_\gamma H^0(\gamma^* TM)\right) \\ - \xi - & \mapsto \nabla_\xi^0 \partial + \tilde X + & \mapsto \nabla_{\tilde X}^0 \partial \end{align*} is such that \[