lie-algebras-and-their-representations

diff --git a/sections/introduction.tex b/sections/introduction.tex
@@ -727,8 +727,9 @@ century. Specifically, we find\dots
   derivation \(C^\infty(G) \to C^\infty(G)\). All other \(G\)-invariant
   differential operators are generated by invariant operators of order \(0\)
   and \(1\). Hence \(\operatorname{Diff}(G)^G\) is generated by
-  \(\operatorname{Der}(G)^G + K\) -- here \(\operatorname{Der}(G)^G \subset
-  \operatorname{Der}(G)\) denotes the Lie subalgebra of invariant derivations.
+  \(\operatorname{Der}(G)^G + \mathbb{R}\) -- here \(\operatorname{Der}(G)^G
+  \subset \operatorname{Der}(G)\) denotes the Lie subalgebra of invariant
+  derivations.
 
   Now recall that there is a canonical isomorphism of Lie algebras
   \(\mathfrak{X}(G) \isoto \operatorname{Der}(G)\). This isomorphism takes left
@@ -751,8 +752,8 @@ century. Specifically, we find\dots
   Since \(\mathcal{U}(\mathfrak{g})\) is generated by the image of the
   inclusion \(\mathfrak{g} \to \mathcal{U}(\mathfrak{g})\), this implies \(\ker
   \tilde f = 0\). Given that \(\operatorname{Diff}(G)^G\) is generated by
-  \(\operatorname{Der}(G)^G + K\), this also goes to show \(\tilde f\) is
-  surjective.
+  \(\operatorname{Der}(G)^G + \mathbb{R}\), this also goes to show \(\tilde f\)
+  is surjective.
 \end{proof}
 
 As one would expect, the same holds for complex Lie groups and algebraic groups