- Commit
- f7480a43064297b4680547cd687088512041f0c4
- Parent
- 85ee514ac45d91082b890b792364e8eab2c9cf38
- Author
- Pablo <pablo-escobar@riseup.net>
- Date
Reordered the contents of the chapter on the general finite-dimensional setting
Source code for my notes on representations of semisimple Lie algebras and Olivier Mathieu's classification of simple weight modules
Reordered the contents of the chapter on the general finite-dimensional setting
2 files changed, 156 insertions, 73 deletions
Status | File Name | N° Changes | Insertions | Deletions |
Modified | sections/semisimple-algebras.tex | 215 | 149 | 66 |
Modified | sections/sl2-sl3.tex | 14 | 7 | 7 |
diff --git a/sections/semisimple-algebras.tex b/sections/semisimple-algebras.tex @@ -362,47 +362,13 @@ then\dots \begin{theorem}\label{thm:weights-congruent-mod-root} The weights of an irreducible representation \(V\) of \(\mathfrak{g}\) are all congruent module the root lattice \(Q = \ZZ \Delta\) of \(\mathfrak{g}\). + In other words, all weights of \(V\) lie in the same \(Q\)-coset in + \(\mfrac{\mathfrak{h}^*}{Q}\). \end{theorem} -% TODOO: Turn this into a proper discussion of basis and give the idea of the -% proof of existance of basis? -To proceed further, as in the case of \(\mathfrak{sl}_3(K)\) we have to fix a -direction in \(\mathfrak{h}^*\) -- i.e. we fix a linear function -\(\mathfrak{h}^* \to \QQ\) such that \(Q\) lies outside of its kernel. This -choice induces a partition \(\Delta = \Delta^+ \cup \Delta^-\) of the set of -roots of \(\mathfrak{g}\) and once more we find\dots - -\begin{definition} - The elements of \(\Delta^+\) and \(\Delta^-\) are called \emph{positive} and - \emph{negative roots}, respectively. The subalgebra \(\mathfrak{b} = - \mathfrak{h} \oplus \bigoplus_{\alpha \in \Delta^+} \mathfrak{g}_\alpha\) is - called \emph{the Borel subalgebra associated with \(\mathfrak{h}\)}. -\end{definition} - -\begin{theorem} - There is a weight vector \(v \in V\) that is killed by all positive root - spaces of \(\mathfrak{g}\). -\end{theorem} - -% TODO: Here we may take a weight of maximal height, but why is it unique? -% TODO: We don't really need to talk about height tho, we may simply take a -% weight that maximizes B(gamma, lambda) in QQ -% TODOO: Either way, we need to move this to after the discussion on the -% integrality of weights -\begin{proof} - It suffices to note that if \(\lambda\) is the weight of \(V\) lying the - furthest along the direction we chose and \(V_{\lambda + \alpha} \ne 0\) for - some \(\alpha \in \Delta^+\) then \(\lambda + \alpha\) is a weight that is - furthest along the direction we chose than \(\lambda\), which contradicts the - definition of \(\lambda\). -\end{proof} - -Accordingly, we call \(\lambda\) \emph{the highest weight of \(V\)}, and we -call any \(v \in V_\lambda\) \emph{a highest weight vector}. The strategy then -is to describe all weight spaces of \(V\) in terms of \(\lambda\) and \(v\), as -in theorem~\ref{thm:sl3-irr-weights-class}, and unsurprisingly we do so by -reproducing the proof of the case of \(\mathfrak{sl}_3(K)\). Namely, we -show\dots +Again, we may levarage our knowlage of \(\mathfrak{sl}_2(K)\) to obtain further +restrictions on the geometry of the space of weights of \(V\). Namelly, such as +in the case of \(\mathfrak{sl}_3(K)\) we show\dots \begin{proposition}\label{thm:distinguished-subalgebra} Given a root \(\alpha\) of \(\mathfrak{g}\) the subspace @@ -414,7 +380,7 @@ show\dots \begin{corollary}\label{thm:distinguished-subalg-rep} For all weights \(\mu\), the subspace \[ - V_\mu[\alpha] = \bigoplus_k V_{\mu + k \alpha} + \bigoplus_k V_{\mu + k \alpha} \] is invariant under the action of the subalgebra \(\mathfrak{s}_\alpha\) and the weight spaces in this string match the eigenspaces of \(h\). @@ -436,49 +402,161 @@ satisfies \end{align*} The elements \(E_\alpha, F_\alpha \in \mathfrak{g}\) are not uniquely -determined by this condition, but \(H_\alpha\) is. The second statement of -corollary~\ref{thm:distinguished-subalg-rep} imposes a restriction on the -weights of \(V\). Namely, if \(\mu\) is a weight, \(\mu(H_\alpha)\) is an -eigenvalue of \(h\) in some representation of \(\mathfrak{sl}_2(K)\), so -that\dots +determined by this condition, but \(H_\alpha\) is. As promised, the second +statement of corollary~\ref{thm:distinguished-subalg-rep} imposes strong +restrictions on the weights of \(V\). Namely, if \(\lambda\) is a weight, +\(\lambda(H_\alpha)\) is an eigenvalue of \(h\) in some representation of +\(\mathfrak{sl}_2(K)\), so it must be an integer. In other words\dots + +\begin{definition}\label{def:weight-lattice} + The lattice \(P = \{ \lambda \in \mathfrak{h}^* : \lambda(H_\alpha) \in + \mathbb{Z} \, \forall \alpha \in \Delta \} \subset \mathfrak{h}^*\) is called + \emph{the weight lattice of \(\mathfrak{g}\)}. +\end{definition} + +\begin{proposition}\label{thm:weights-fit-in-weight-lattice} + The weights of an irreducible representation \(V\) of \(\mathfrak{g}\) is Lie + in the weight lattice \(P\). +\end{proposition} + +We call the elements of \(P\) \emph{integral}. +Proposition~\ref{thm:weights-fit-in-weight-lattice} is clearly analogous to +corollary~\ref{thm:sl3-weights-fit-in-weight-lattice}. In fact, the weight +lattice of \(\mathfrak{sl}_3(K)\) -- as in definition~\ref{def:weight-lattice} +-- is precisely \(\mathbb{Z} \alpha_1 \oplus \mathbb{Z} \alpha_2 \oplus +\mathbb{Z} \alpha_3\). + +To proceed further, we would like to take \emph{the highest weight of \(V\)} as +in section~\ref{sec:sl3-reps}, but the meaning of \emph{highest} is again +unclear in this situation. We could simply fix a linear function \(\mathbb{Q} P +\to \mathbb{Q}\) -- as we did in section~\ref{sec:sl3-reps} -- and choose a +weight \(\lambda\) of \(V\) that maximizes this functional, but at this point +it is conveniant to introduce some additional tools to our arsenal. This tools +are called \emph{basis}. + +\begin{definition}\label{def:basis-of-root} + A subset \(\Sigma = \{\beta_1, \ldots, \beta_k\} \subset \Delta\) of linearly + independant roots is called \emph{a basis for \(\Delta\)} if, given \(\alpha + \in \Delta\), there are \(n_1, \ldots, n_k \in \mathbb{N}\) such that + \(\alpha = \pm(n_1 \beta_1 + \cdots + n_k \beta_k)\). +\end{definition} + +The interesting thing about basis for \(\Delta\) is that they allow us to +compare weights of a given representation. At this point the reader should be +asking himself: how? Definition~\ref{def:basis-of-root} doesn't exactly screem +``comparison''. Well, the thing is that any choice of basis induces a partial +order in \(Q\), where elements are ordered by their \emph{hights}. + +\begin{definition} + Let \(\Sigma = \{\beta_1, \ldots, \beta_k\}\) be a basis for \(\Delta\). + Given \(\alpha = n_1 \beta_1 + \cdots + n_2 \beta_2 \in Q\) with \(n_1, + \ldots, n_k \in \mathbb{Z}\), we call the number \(h(\alpha) = n_1 + \cdots + + n_k \in \mathbb{Z}\) \emph{the height of \(\alpha\)}. We say that \(\alpha + \preceq \beta\) if \(h(\alpha) \le h(\beta)\). +\end{definition} + +\begin{definition} + Given a basis \(\Sigma\) for \(\Delta\), there is a canonical partition + \(\Delta^+ \cup \Delta^- = \Delta\), where \(\Delta^+ = \{ \alpha \in \Delta + : \alpha \succeq 0 \}\) and \(\Delta^- = \{ \alpha \in \Delta : \alpha + \preceq 0 \}\). The elements of \(\Delta^+\) and \(\Delta^-\) are called + \emph{positive} and \emph{negative roots}, respectively. +\end{definition} + +\begin{definition} + Let \(\Sigma\) be a basis for \(\Delta\). The subalgebra \(\mathfrak{b} = + \mathfrak{h} \oplus \bigoplus_{\alpha \in \Delta^+} \mathfrak{g}_\alpha\) is + called \emph{the Borel subalgebra associated with \(\mathfrak{h}\) and + \(\Sigma\)}. +\end{definition} + +It should be obvious that the binary relation \(\preceq\) in \(Q\) is a partial +order. In addition, we may compare the elements of a given \(Q\)-coset +\(\lambda + Q\) by comparing their difference with \(0 \in Q\). In other words, +we say \(\lambda \preceq \mu\) if \(\lambda - \mu \preceq 0\) for \(\lambda \in +\mu + Q\). In particular, since the weights of \(V\) all lie in a single +\(Q\)-coset, we may compare them in this fashion. Given a basis \(\Sigma\) for +\(\Delta\) we may take ``the highest weight of \(V\)'' as a maximal weight +\(\lambda\) of \(V\). The obvious question then is: can we always find a basis +for \(\Delta\)? \begin{proposition} - The weights \(\mu\) of an irreducible representation \(V\) of - \(\mathfrak{g}\) are so that \(\mu(H_\alpha) \in \ZZ\) for each \(\alpha \in - \Delta\). + There is a basis \(\Sigma\) for \(\Delta\). \end{proposition} -Once more, the lattice \(P = \{ \lambda \in \mathfrak{h}^* : \lambda(H_\alpha) -\in \ZZ, \forall \alpha \in \Delta \}\) is called \emph{the weight lattice of -\(\mathfrak{g}\)}, and we call the elements of \(P\) \emph{integral}. Finally, -another important consequence of theorem~\ref{thm:distinguished-subalgebra} -is\dots +The intuition behind the proof of this proposition is similar to our original +idea of fixing a direction in \(\mathfrak{h}^*\) in the case of +\(\mathfrak{sl}_3(K)\). Namely, one can show that \(B(\alpha, \beta) \in +\mathbb{Z}\) for all \(\alpha, \beta \in \Delta\), so that the Killing form +\(B\) restricts to a nondegenerate form \(\mathbb{Q} \Delta \times \mathbb{Q} +\Delta \to \mathbb{Q}\). We can then fix a nonzero vector \(\gamma \in +\mathbb{Q} \Delta\) and consider the orthogonal projection \(f : \mathbb{Q} +\Delta \to \mathbb{Q} \gamma \cong \mathbb{Q}\). We say a root \(\alpha \in +\Delta\) is \emph{positive} if \(f(\alpha) > 0\), and we call a positive root +\(\alpha\) \emph{simple} if it cannot be written as the sum two other positive +roots. The subset \(\Sigma \subset \Delta\) of all simple roots is a basis for +\(\Delta\), and all other basis can be shown to arise in this way. + +Fix some basis \(\Sigma\) for \(\Delta\), with corresponding decomposition +\(\Delta^+ \cup \Delta^- = \Delta\). Let \(\lambda\) be a maximal weight of +\(V\). We call \(\lambda\) \emph{the highest weight of \(V\)}, and we call any +nonzero \(v \in V_\lambda\) \emph{a highest weight vector}. The strategy then +is to describe all weight spaces of \(V\) in terms of \(\lambda\) and \(v\), as +in theorem~\ref{thm:sl3-irr-weights-class}. Unsurprisingly we do so by +reproducing the proof of the case of \(\mathfrak{sl}_3(K)\). + +First, we note that any highest weight vector \(v \in V_\lambda\) is +annihilated by all positive root spaces, for if \(\alpha \in \Delta^+\) then +\(E_\alpha v \in V_{\lambda + \alpha}\) must be zero -- or otherwise we would +have that \(\lambda + \alpha\) is a weight with \(\lambda \prec \lambda + +\alpha\). In particular, +\[ + \bigoplus_{k \in \mathbb{Z}} V_{\lambda - k \alpha} + = \bigoplus_{k \in \mathbb{N}} V_{\lambda - k \alpha} +\] +and \(\lambda(H_\alpha)\) is the right-most eigenvalue of the action of \(h\) +in the \(\mathfrak{sl}_2(K)\)-module \(\bigoplus_k V_{\lambda - k \alpha}\). + +This has a number of important consequences. For instance\dots +% TODO: Change the notation for T_alpha \begin{corollary} If \(\alpha \in \Delta^+\) and \(T_\alpha : \mathfrak{h}^* \to \mathfrak{h}^*\) is the reflection in the hyperplane perpendicular to - \(\alpha\) with respect to the Killing form, - corollary~\ref{thm:distinguished-subalg-rep} implies that all \(\nu \in P\) - lying inside the line connecting \(\mu\) and \(T_\alpha \mu\) are weights -- - i.e. \(V_\nu \ne 0\). + \(\alpha\) with respect to the Killing form, the weights of \(V\) occuring in + the line joining \(\lambda\) and \(T_\alpha\) are precisely the \(\mu \in P\) + lying between \(\lambda\) and \(T_\alpha \lambda\). \end{corollary} \begin{proof} - It suffices to note that \(\nu \in V_\mu[\alpha]\) -- see appendix D of - \cite{fulton-harris} for further details. + Notice that any \(\mu \in P\) in the line joining \(\lambda\) and \(T_\alpha + \lambda\) has the form \(\mu = \lambda - k \alpha\) for some \(k\), so that + \(V_\mu\) corresponds the eigenspace associated with the eigenvalue + \(\lambda(H_\alpha) - 2k\) of the action of \(h\) in \(\bigoplus_k V_{\lambda + - k \alpha}\). If \(\mu\) lies between \(\lambda\) and \(T_\alpha \lambda\) + then \(k\) lies between \(0\) and \(\lambda(H_\alpha)\), in which case + \(V_\mu \neq 0\) and therefore \(\mu\) is a weight. + + On the other hand, if \(\mu\) does not lie between \(\lambda\) and \(T_\alpha + \lambda\) then either \(k < 0\) or \(k > \lambda(H_\alpha)\). Suppose \(\mu\) + is a weight. In the first case \(\mu \succ \lambda\), a contradiction. On the + second case the fact that \(V_\mu \ne 0\) implies \(V_{\lambda + (k - + \lambda(H_\alpha)) \alpha} \ne 0 = V_{T_\alpha \mu}\), which contradicts the + fact that \(V_{\lambda + \ell \alpha} = 0\) for all \(\ell \ge 0\). \end{proof} +This is entirely analogous to the situation of \(\mathfrak{sl}_3(K)\), where we +found that the weights of the irreducible representations formed a continuous +string symmetric with respect to the lines \(K \alpha\) with \(B(\alpha_i - +\alpha_j, \alpha) = 0\). As in the case of \(\mathfrak{sl}_3(K)\), the same +class of arguments leads us to the conclusion\dots + \begin{definition} We refer to the group \(\mathcal{W} = \langle T_\alpha : \alpha \in \Delta^+ \rangle \subset \operatorname{O}(\mathfrak{h}^*)\) as \emph{the Weyl group of \(\mathfrak{g}\)}. \end{definition} -This is entirely analogous to the situation of \(\mathfrak{sl}_3(K)\), where we -found that the weights of the irreducible representations were symmetric with -respect to the lines \(K \alpha\) with \(B(\alpha_i - \alpha_j, \alpha) = 0\). -Indeed, the same argument leads us to the conclusion\dots - \begin{theorem}\label{thm:irr-weight-class} The weights of an irreducible representation \(V\) of \(\mathfrak{g}\) with highest weight \(\lambda\) are precisely the elements of the weight lattice @@ -489,7 +567,13 @@ Indeed, the same argument leads us to the conclusion\dots Now the only thing we are missing for a complete classification is an existence and uniqueness theorem analogous to theorem~\ref{thm:sl2-exist-unique} and -theorem~\ref{thm:sl3-existence-uniqueness}. Lo and behold\dots +theorem~\ref{thm:sl3-existence-uniqueness}. It is already clear from the +previous discussion that if \(\lambda\) is the highest weight of \(V\) then +\(\lambda(H_\alpha) \ge 0\) for all positive roots \(\alpha\). Another way of +putting it is to say that having \(\lambda(H_\alpha) \ge 0\) for all \(\alpha +\in \Delta^+\) is a necessary condition for the existance of irreducible +representations with highest weight given by \(\lambda\). Surprisingly, this +condition is also sufficient. In other words\dots \begin{definition} An element \(\lambda\) of \(P\) such that \(\lambda(H_\alpha) \ge 0\) for all @@ -749,7 +833,6 @@ are really interested in is\dots of the maximal subrepresentation of \(M(\lambda)\), the projection \(v^+ + N(\lambda) \in V\) is nonzero. - % TODO: Why is V_mu = M(lambda)_mu + N(lambda)? Turn this into a proposition? We now claim that \(v^+ + N(\lambda) \in V_\lambda\). Indeed, \[ H (v^+ + N(\lambda))
diff --git a/sections/sl2-sl3.tex b/sections/sl2-sl3.tex @@ -221,7 +221,7 @@ To conclude our analysis all it's left is to show that for each \(n\) such \(V\) does indeed exist and is irreducible. Surprinsingly, we have already encountered such a \(V\). -\begin{theorem}\label{thm:irr-rep-of-sl2-exists} +\begin{theorem}\label{thm:sl2-exist-unique} For each \(n \ge 0\) there exists a unique irreducible representation of \(\mathfrak{sl}_2(K)\) whose left-most eigenvalue of \(h\) is \(n\). \end{theorem} @@ -299,7 +299,7 @@ chapter, but for now we note that perhaps the most fundamental property of annihilated by \(e\)} -- that being the generator of the right-most eigenspace of \(h\). This was instrumental to our explicit description of the irreducible representations of \(\mathfrak{sl}_2(K)\) culminating in -theorem~\ref{thm:irr-rep-of-sl2-exists}. +theorem~\ref{thm:sl2-exist-unique}. Our fist task is to find some analogue of \(h\) in \(\mathfrak{sl}_3(K)\), but it's still unclear what exactly we are looking for. We could say we're looking @@ -602,8 +602,8 @@ As a first consequence of this, we show\dots called \emph{the weight lattice of \(\mathfrak{sl}_3(K)\)}. \end{definition} -\begin{corollary} - Every weight \(\lambda\) of \(V\) lies in the weight lattice \(\lambda\). +\begin{corollary}\label{thm:sl3-weights-fit-in-weight-lattice} + Every weight \(\lambda\) of \(V\) lies in the weight lattice \(P\). \end{corollary} \begin{proof} @@ -643,8 +643,8 @@ There's a clear parallel between the case of \(\mathfrak{sl}_3(K)\) and that of lattice \(P = \ZZ\) and were congruent modulo the sublattice \(Q = 2 \ZZ\). Among other things, this last result goes to show that the diagrams we've been drawing are in fact consistant with the theory we've developed. Namely, since -all weights lie in the rational span of \(\{\alpha_1, \alpha_2, \alpha_3\}\) in -\(\mathfrak{h}^*\) we may as well draw them in the Cartesia plane. +all weights lie in the rational span of \(\{\alpha_1, \alpha_2, \alpha_3\}\), +we may as well draw them in the Cartesia plane. To proceed we once more refer to the previously established framework: next we saw that the eigenvalues of \(h\) formed an unbroken string of integers @@ -939,7 +939,7 @@ Finally\dots Having found all of the weights of \(V\), the only thing we're missing is an existence and uniqueness theorem analogous to -theorem~\ref{thm:irr-rep-of-sl2-exists}. In other words, our next goal is +theorem~\ref{thm:sl2-exist-unique}. In other words, our next goal is establishing\dots \begin{theorem}\label{thm:sl3-existence-uniqueness}