- Commit
- c93e7373196dc96e6b9d65275f85ce3b4dffcc59
- Parent
- 2dc7ea2f5adfbd9db880ef1b9864a09597635d7d
- Author
- Pablo <pablo-pie@riseup.net>
- Date
Changed the notation for the number of boundary components
b → p
My M2 Memoire on mapping class groups & their representations
Changed the notation for the number of boundary components
b → p
7 files changed, 182 insertions, 177 deletions
Status | File Name | N° Changes | Insertions | Deletions |
Modified | images/lickorish-gens-gen-2.svg | 35 | 18 | 17 |
Modified | images/lickorish-gens-korkmaz-proof.svg | 33 | 17 | 16 |
Modified | images/lickorish-gens.svg | 35 | 19 | 16 |
Modified | sections/introduction.tex | 14 | 7 | 7 |
Modified | sections/presentation.tex | 92 | 46 | 46 |
Modified | sections/representations.tex | 102 | 51 | 51 |
Modified | sections/twists.tex | 48 | 24 | 24 |
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diff --git a/sections/introduction.tex b/sections/introduction.tex @@ -46,18 +46,18 @@ geometry of the curves in \(S\) and their intersections. For example\dots \end{lemma} \begin{proof} - Let \(S = S_{g, r}^b\) and consider the surface \(S_{\alpha \alpha'}\) + Let \(S = S_{g, r}^p\) and consider the surface \(S_{\alpha \alpha'}\) obtained by cutting \(S\) across \(\alpha\) and \(\alpha'\), as in Figure~\ref{fig:change-of-coordinates}. Since \(\alpha\) and \(\alpha'\) are nonseparating, this surface has genus \(g - 1\) and one additional boundary component \(\delta \subset \partial S_{\alpha \beta}\), so \(S_{\alpha \beta} - \cong S_{g-1,r}^{b+1}\). The boundary component \(\delta\) is naturally + \cong S_{g-1,r}^{p+1}\). The boundary component \(\delta\) is naturally subdived into the four arcs in Figure~\ref{fig:change-of-coordinates}, each corresponding to one of the curves \(\alpha\) and \(\alpha'\) in \(S\). By identifying the pairs of arcs corresponding to the same curve we obtain the surface \(\mfrac{S_{\alpha \beta}}{\sim} \cong S\). - Similarly, \(S_{\beta \beta'} \cong S_{g-1, r}^{b+1}\) also has an additional + Similarly, \(S_{\beta \beta'} \cong S_{g-1, r}^{p+1}\) also has an additional boundary component \(\delta' \subset \partial S_{\beta \beta'}\) subdivided into four arcs. Now by the classification of surfaces we can find an orientation-preserving homemorphism \(\tilde\phi : S_{\alpha \alpha'} \isoto @@ -72,10 +72,10 @@ geometry of the curves in \(S\) and their intersections. For example\dots \begin{figure}[ht] \centering \includegraphics[width=.8\linewidth]{images/change-of-coords-cut.eps} - \caption{By cutting $S_{g, r}^b$ across $\alpha$ we obtain $S_{g-1, - r}^{b+2}$, where $\alpha'$ deterimines a yellow arc joining the two - additional boundary components. Now by cutting $S_{g-1, r}^{b+2}$ across this - arc we obtain $S_{g-1,r}^b$, with the added boundary component subdivided + \caption{By cutting $S_{g, r}^p$ across $\alpha$ we obtain $S_{g-1, + r}^{p+2}$, where $\alpha'$ deterimines a yellow arc joining the two + additional boundary components. Now by cutting $S_{g-1, r}^{p+2}$ across this + arc we obtain $S_{g-1,r}^p$, with the added boundary component subdivided into the four arcs corresponding to $\alpha$ and $\alpha'$.} \label{fig:change-of-coordinates} \end{figure}
diff --git a/sections/presentation.tex b/sections/presentation.tex @@ -38,21 +38,21 @@ interesting relations between the corresponding Dehn twists in \(\Mod(S)\). For example\dots \begin{proposition}\label{thm:trivial-abelianization} - The Abelianization \(\Mod(S_g^b)^\ab = \mfrac{\Mod(S_g^b)}{[\Mod(S_g), - \Mod(S_g)]}\) is cyclic. Moreover, if \(g \ge 3\) then \(\Mod(S_g^b)^\ab = + The Abelianization \(\Mod(S_g^p)^\ab = \mfrac{\Mod(S_g^p)}{[\Mod(S_g), + \Mod(S_g)]}\) is cyclic. Moreover, if \(g \ge 3\) then \(\Mod(S_g^p)^\ab = 1\). In other words, \(\Mod(S_g)\) is a perfect group for \(g \ge 3\). \end{proposition} \begin{proof} - By Theorem~\ref{thm:lickorish-gens}, \(\Mod(S_g^b)^\ab\) is generated by the + By Theorem~\ref{thm:lickorish-gens}, \(\Mod(S_g^p)^\ab\) is generated by the image of the Lickrish generators, which are all conjugate and thus represent the same class in the Abelianization. In fact, any nonseparating \(\alpha - \subset S_g^b\) is conjugate to the Lickorish generators too, so - \(\Mod(S_g^b)^\ab = \langle [\alpha] \rangle\). + \subset S_g^p\) is conjugate to the Lickorish generators too, so + \(\Mod(S_g^p)^\ab = \langle [\alpha] \rangle\). - Now for \(g \ge 3\) we can embed \(S_0^4\) in \(S_g^b\) in such a way that + Now for \(g \ge 3\) we can embed \(S_0^4\) in \(S_g^p\) in such a way that all the corresponding curves \(\alpha, \beta, \gamma, \delta_1, \ldots, - \delta_4 \subset S_g^b\) are nonseparating, as shown in + \delta_4 \subset S_g^p\) are nonseparating, as shown in Figure~\ref{fig:latern-relation-trivial-abelianization}. The lantern relation (\ref{eq:latern-relation}) then becomes \[ @@ -62,14 +62,14 @@ example\dots + [\tau_{\delta_3}] + [\tau_{\delta_4}] = 4 \cdot [\tau_\alpha] \] - in \(\Mod(S_g^b)^\ab\). In other words, \([\tau_\alpha] = 0\) and thus - \(\Mod(S_g^b)^\ab = 0\). + in \(\Mod(S_g^p)^\ab\). In other words, \([\tau_\alpha] = 0\) and thus + \(\Mod(S_g^p)^\ab = 0\). \end{proof} \begin{figure}[ht] \centering \includegraphics[width=.5\linewidth]{images/lantern-relation-trivial-abelianization.eps} - \caption{The embedding of $S_0^4$ in $S_g^b$ for $g \ge 3$.} + \caption{The embedding of $S_0^4$ in $S_g^p$ for $g \ge 3$.} \label{fig:latern-relation-trivial-abelianization} \end{figure} @@ -89,14 +89,14 @@ presentations of \(\Mod(S_g)\) for \(g \le 2\) to show the Abelianization is giv for closed surfaces with small genus. In \cite{korkmaz-mccarthy} Korkmaz-McCarthy showed that -eventhough \(\Mod(S_2^b)\) is not perfect, its commutator subgroup is. -In addition, they also show \([\Mod(S_g^b), \Mod(S_g^b)]\) is normaly generated +eventhough \(\Mod(S_2^p)\) is not perfect, its commutator subgroup is. +In addition, they also show \([\Mod(S_g^p), \Mod(S_g^p)]\) is normaly generated by a single mapping class. \begin{proposition}\label{thm:commutator-is-perfect} - The commutator subgroup \(\Mod(S_2^b)' = [\Mod(S_2^b), \Mod(S_2^b)]\) is - perfect -- i.e. \(\Mod(S_2^b)^{(2)} = [\Mod(S_2^b)', \Mod(S_2^b)']\) is the - whole of \(\Mod(S_2^b)'\). + The commutator subgroup \(\Mod(S_2^p)' = [\Mod(S_2^p), \Mod(S_2^p)]\) is + perfect -- i.e. \(\Mod(S_2^p)^{(2)} = [\Mod(S_2^p)', \Mod(S_2^p)']\) is the + whole of \(\Mod(S_2^p)'\). \end{proposition} \begin{proposition}\label{thm:commutator-normal-gen} @@ -217,10 +217,10 @@ we get\dots To get from \(S_{0, n}^1\) to surfaces of genus \(g > 0\) we may consider the \emph{hyperelliptic involution} \(\iota : S_g \isoto S_g\) which rotates \(S_g\) by \(\pi\) around some axis, as shown in -Figure~\ref{fig:hyperelliptic-involution}. Given \(\ell < g\) and \(b = 1, 2\), -we can also embed \(S_\ell^b\) in \(S_g\) in such way that \(\iota\) restricts -to an involution\footnote{This involution does not fix $\partial S_\ell^b$ -point-wise.} \(S_\ell^b \isoto S_\ell^b\). +Figure~\ref{fig:hyperelliptic-involution}. Given \(\ell < g\) and \(p = 1, 2\), +we can also embed \(S_\ell^p\) in \(S_g\) in such way that \(\iota\) restricts +to an involution\footnote{This involution does not fix $\partial S_\ell^p$ +point-wise.} \(S_\ell^p \isoto S_\ell^p\). \begin{figure}[ht] \centering @@ -232,13 +232,13 @@ point-wise.} \(S_\ell^b \isoto S_\ell^b\). It is clear from Figure~\ref{fig:hyperelliptic-involution} that the quotients \(\mfrac{S_\ell^1}{\iota}\) and \(\mfrac{S_\ell^2}{\iota}\) are both disks, with boundary corresponding to the projection of the boundaries of \(S_\ell^1\) -and \(S_\ell^2\), respectively. Given \(b = 1, 2\), the quotient map \(S_\ell^b -\to \mfrac{S_\ell^b}{\iota} \cong \mathbb{D}^2\) is a double cover with \(2\ell + +and \(S_\ell^2\), respectively. Given \(p = 1, 2\), the quotient map \(S_\ell^p +\to \mfrac{S_\ell^p}{\iota} \cong \mathbb{D}^2\) is a double cover with \(2\ell + b\) branch points corresponding to the fixed points of \(\iota\). We may thus -regard \(\mfrac{S_\ell^b}{\iota}\) as the disk \(S_{0, 2\ell + b}^1\) with +regard \(\mfrac{S_\ell^p}{\iota}\) as the disk \(S_{0, 2\ell + b}^1\) with \(2\ell + b\) punctures in its interior, as shown in Figure~\ref{fig:hyperelliptic-covering}. We also draw the curves \(\alpha_1, -\ldots, \alpha_{2\ell} \subset S_\ell^b\) of the Humphreys generators of +\ldots, \alpha_{2\ell} \subset S_\ell^p\) of the Humphreys generators of \(\Mod(S_g)\). Since these curves are invariant under the action of \(\iota\), they descend to arcs \(\bar{\alpha}_1, \ldots, \bar{\alpha}_{2\ell + b} \subset S_{0, 2\ell + b}^1\) joining the punctures of the quotient surface. @@ -262,36 +262,36 @@ the quotient surfaces and their mapping classes, known as \emph{the symmetric mapping clases}. \begin{definition} - Let \(\ell \ge 0\) and \(b = 1, 2\). The \emph{group of symmetric - homeomorphisms of \(S_\ell^b\)} is \(\SHomeo^+(S_\ell^b, \partial S_\ell^b) = - \{\phi \in \Homeo^+(S_\ell^b, \partial S_\ell^b) : [\phi, \iota] = 1\}\). The - \emph{symmetric mapping class group of \(S_\ell^b\)} is the subgroup - \(\SMod(S_\ell^1) = \{ [\phi] \in \Mod(S_\ell^b) : \phi \in - \SHomeo^+(S_\ell^b, \partial S_\ell^b) \}\). + Let \(\ell \ge 0\) and \(p = 1, 2\). The \emph{group of symmetric + homeomorphisms of \(S_\ell^p\)} is \(\SHomeo^+(S_\ell^p, \partial S_\ell^p) = + \{\phi \in \Homeo^+(S_\ell^p, \partial S_\ell^p) : [\phi, \iota] = 1\}\). The + \emph{symmetric mapping class group of \(S_\ell^p\)} is the subgroup + \(\SMod(S_\ell^1) = \{ [\phi] \in \Mod(S_\ell^p) : \phi \in + \SHomeo^+(S_\ell^p, \partial S_\ell^p) \}\). \end{definition} -Fix \(b = 1\) or \(2\). It follows from the universal property of quotients -that any \(\phi \in \SHomeo^+(S_\ell^b, \partial S_\ell^b)\) defines a +Fix \(p = 1\) or \(2\). It follows from the universal property of quotients +that any \(\phi \in \SHomeo^+(S_\ell^p, \partial S_\ell^p)\) defines a homeomorphism \(\bar \phi : S_{0, 2\ell+b}^1 \isoto S_{0, 2\ell+b}^1\). This yeilds a homomorphism of topological groups \begin{align*} - \SHomeo^+(S_\ell^b, \partial S_\ell^b) + \SHomeo^+(S_\ell^p, \partial S_\ell^p) & \to \Homeo^+(S_{0, 2\ell + b}^1, \partial S_{0, 2\ell + b}^1) \\ \phi & \mapsto \bar \phi, \end{align*} which is surjective because any \(\psi \in \Homeo^+(S_{0, 2\ell + b}^1, -\partial S_{0, 2\ell + b}^1)\) lifts to \(S_\ell^b\). +\partial S_{0, 2\ell + b}^1)\) lifts to \(S_\ell^p\). -It is also not hard to see \(\SHomeo^+(S_\ell^b, \partial S_\ell^b) \to +It is also not hard to see \(\SHomeo^+(S_\ell^p, \partial S_\ell^p) \to \Homeo^+(S_{0, 2\ell + b}^1, \partial S_{0, 2\ell + b}^1)\) is injective: the only cadidates for elements of its kernel are \(1\) and \(\iota\), but -\(\iota\) is not an element of \(\SHomeo^+(S_\ell^b, \partial S_\ell^b)\) since -it does not fix \(\partial S_\ell^b\) point-wise. Now since we have a +\(\iota\) is not an element of \(\SHomeo^+(S_\ell^p, \partial S_\ell^p)\) since +it does not fix \(\partial S_\ell^p\) point-wise. Now since we have a continuous bijective homomorphism we find \[ \begin{split} - \pi_0(\SHomeo^+(S_\ell^b, \partial S_\ell^b)) + \pi_0(\SHomeo^+(S_\ell^p, \partial S_\ell^p)) & \cong \pi_0(\Homeo^+(S_{0, 2\ell+b}^1, \partial S_{0, 2\ell+b}^1)) \\ & = \mfrac{\Homeo^+(S_{0,2\ell+b}^1, \partial S_{0, 2\ell+b}^1)}{\simeq} \\ & = \Mod(S_{0, 2\ell+b}^1) \\ @@ -299,27 +299,27 @@ continuous bijective homomorphism we find \end{split} \] -We would like to say \(\pi_0(\SHomeo^+(S_\ell^b, \partial S_\ell^b)) = -\SMod(S_\ell^b)\), but a priori the story looks a little more complicated: -\(\phi, \psi \in \SHomeo^+(S_\ell^b, \partial S_\ell^b)\) define the same class -in \(\SMod(S_\ell^b)\) if they are isotopic, but they may not lie in same -connected component of \(\SHomeo^+(S_\ell^b, \partial S_\ell^b)\) if they are +We would like to say \(\pi_0(\SHomeo^+(S_\ell^p, \partial S_\ell^p)) = +\SMod(S_\ell^p)\), but a priori the story looks a little more complicated: +\(\phi, \psi \in \SHomeo^+(S_\ell^p, \partial S_\ell^p)\) define the same class +in \(\SMod(S_\ell^p)\) if they are isotopic, but they may not lie in same +connected component of \(\SHomeo^+(S_\ell^p, \partial S_\ell^p)\) if they are not isotopic \emph{through symmetric homeomorphisms}. Birman-Hilden \cite{birman-hilden} showed that this is never the case. \begin{theorem}[Birman-Hilden] - If \(\phi, \psi \in \SHomeo^+(S_\ell^b, \partial S_\ell^b)\) are isotopic + If \(\phi, \psi \in \SHomeo^+(S_\ell^p, \partial S_\ell^p)\) are isotopic then \(\phi\) and \(\psi\) are isotopic through symmetric homeomorphisms. In particular, there is an isomorphism \begin{align*} - \SMod(S_\ell^b) & \isoto \Mod(S_{0, 2\ell + b}) \\ + \SMod(S_\ell^p) & \isoto \Mod(S_{0, 2\ell + b}) \\ [\phi] & \mapsto [\bar \phi]. \end{align*} \end{theorem} \begin{example} Using the notation of Figure~\ref{fig:hyperelliptic-covering}, the - Birman-Hilden isomorphism \(\SMod(S_\ell^b) \isoto \Mod(S_{0, 2g + b})\) + Birman-Hilden isomorphism \(\SMod(S_\ell^p) \isoto \Mod(S_{0, 2g + b})\) takes \(\tau_{\alpha_i}\) to the half twist \(h_{\bar{\alpha}_i} \in \Mod(S_{0, 2g + b})\). This can be checked by looking at \(\iota\)-invaratiant anular neighborhoods of the curves \(\alpha_i\) -- @@ -335,7 +335,7 @@ not isotopic \emph{through symmetric homeomorphisms}. Birman-Hilden \(\tau_{\bar\delta_1} = \tau_{\bar\delta_2}\). In light of Example~\ref{ex:push-generators-description}, Example~\ref{ex:braid-group-center} gives us the so called \emph{\(k\)-chain - relations} in \(\SMod(S_\ell^b) \subset \Mod(S_g)\). + relations} in \(\SMod(S_\ell^p) \subset \Mod(S_g)\). \[ \arraycolsep=1.4pt \begin{array}{rlcrll}
diff --git a/sections/representations.tex b/sections/representations.tex @@ -16,8 +16,8 @@ goal of this chapter is providing a concise account of Korkmaz' results, starting by\dots \begin{theorem}[Korkmaz]\label{thm:low-dim-reps-are-trivial} - Let \(S_g^b\) be the surface of genus \(g \ge 1\) and \(b\) boundary - components and \(\rho : \Mod(S_g^b) \to \GL_n(\mathbb{C})\) be a linear + Let \(S_g^p\) be the surface of genus \(g \ge 1\) and \(b\) boundary + components and \(\rho : \Mod(S_g^p) \to \GL_n(\mathbb{C})\) be a linear representation with \(n < 2 g\). Then the image of \(\rho\) is Abelian. In particular, if \(g \ge 3\) then \(\rho\) is trivial. \end{theorem} @@ -28,15 +28,15 @@ by induction on \(g\) and tedious case analysis. We begin by the base case \(g = 2\). \begin{proposition}\label{thm:low-dim-reps-are-trivial-base-case} - Given \(\rho : \Mod(S_2^b) \to \GL_n(\mathbb{C})\) with \(n \le 3\), the + Given \(\rho : \Mod(S_2^p) \to \GL_n(\mathbb{C})\) with \(n \le 3\), the image of \(\rho\) is Abelian. \end{proposition} \begin{proof}[Sketch of proof] - Given \(\alpha \subset S_2^b\), let \(L_\alpha = \rho(\tau_\alpha)\) and + Given \(\alpha \subset S_2^p\), let \(L_\alpha = \rho(\tau_\alpha)\) and denote by \(E_{\alpha = \lambda} = \{ v \in \mathbb{C}^n : L_\alpha v = \lambda v \}\) its eigenspaces. Let \(\alpha_1, \alpha_2, \beta_1, \beta_2, - \gamma, \eta_1, \ldots, \eta_{b - 1} \subset S_2^b\) be the curves of the + \gamma, \eta_1, \ldots, \eta_{p-1} \subset S_2^p\) be the curves of the Lickorish generators from Theorem~\ref{thm:lickorish-gens}, as shown in Figure~\ref{fig:lickorish-gens-genus-2}. \begin{figure} @@ -46,12 +46,12 @@ by induction on \(g\) and tedious case analysis. We begin by the base case \(g \label{fig:lickorish-gens-genus-2} \end{figure} - If \(n = 1\) then \(\rho(\Mod(S_2^b)) \subset \GL_1(\mathbb{C}) = + If \(n = 1\) then \(\rho(\Mod(S_2^p)) \subset \GL_1(\mathbb{C}) = \mathbb{C}^\times\) is Abelian. Now if \(n = 2\) or \(3\), by Propositon~\ref{thm:commutator-normal-gen} it suffices to show \(L_{\alpha_1} = L_{\beta_1}\), so that \(\tau_{\alpha_1} \tau_{\beta_1}^{-1} \in \ker - \rho\) and thus \(\Mod(S_2^b)' \subset \ker \rho\) -- i.e. - \(\rho(\Mod(S_2^b))\) is Abelian. Given the braid relation + \rho\) and thus \(\Mod(S_2^p)' \subset \ker \rho\) -- i.e. + \(\rho(\Mod(S_2^p))\) is Abelian. Given the braid relation \begin{equation}\label{eq:braid-rel-induction-basis} L_{\alpha_1} L_{\beta_1} L_{\alpha_1} = L_{\beta_1} L_{\alpha_1} L_{\beta_1}, @@ -138,8 +138,8 @@ by induction on \(g\) and tedious case analysis. We begin by the base case \(g case. We claim that if \(E_{\alpha_2 = \lambda} = E_{\beta_2 = \lambda}\) then - \(E_{\alpha_2 = \lambda}\) is \(\Mod(S_2^b)\)-invariant. Indeed, by change of - coordinates we can always find \(f, g, h_i \in \Mod(S_2^b)\) with + \(E_{\alpha_2 = \lambda}\) is \(\Mod(S_2^p)\)-invariant. Indeed, by change of + coordinates we can always find \(f, g, h_i \in \Mod(S_2^p)\) with \begin{align*} f \cdot [\alpha_2] & = [\alpha_1] & @@ -184,16 +184,16 @@ by induction on \(g\) and tedious case analysis. We begin by the base case \(g \end{align*} In other words, \(E_{\alpha_1 = \lambda} = E_{\alpha_2 = \lambda} = E_{\beta_1 = \lambda} = E_{\beta_2 = \lambda} = E_{\gamma = \lambda} = - E_{\eta_1 = \lambda} = \cdots = E_{\eta_{b - 1} = \lambda}\) is invariant + E_{\eta_1 = \lambda} = \cdots = E_{\eta_{p-1} = \lambda}\) is invariant under the action of all Lickorish generators. - Hence \(\rho\) restricts to a subrepresentation \(\bar \rho : \Mod(S_2^b) \to + Hence \(\rho\) restricts to a subrepresentation \(\bar \rho : \Mod(S_2^p) \to \GL(E_{\alpha_2 = \lambda}) = \GL_2(\mathbb{C})\) -- recall \(E_{\alpha_2 = \lambda} = \mathbb{C} e_1 \oplus \mathbb{C} e_2\). By case (2), \(\bar - \rho(f) = 1\) for all \(f \in \Mod(S_2^b)'\), given that \(\bar - \rho(\Mod(S_2^b))\) is Abelian. Thus + \rho(f) = 1\) for all \(f \in \Mod(S_2^p)'\), given that \(\bar + \rho(\Mod(S_2^p))\) is Abelian. Thus \[ - \rho(\Mod(S_2^b)') \subset + \rho(\Mod(S_2^p)') \subset \begin{pmatrix} 1 & 0 & * \\ 0 & 1 & * \\ @@ -202,7 +202,7 @@ by induction on \(g\) and tedious case analysis. We begin by the base case \(g \] lies inside the group of upper triangular matrices, a solvalbe subgroup of \(\GL_3(\mathbb{C})\). Now by Proposition~\ref{thm:commutator-is-perfect} we - get \(\rho(\Mod(S_2^b)') = 1\): any homomorphism from a perfect group to a + get \(\rho(\Mod(S_2^p)') = 1\): any homomorphism from a perfect group to a solvable group is trivial. Finally, if \(E_{\alpha_2 = \lambda} \ne E_{\beta_2 = \lambda}\) and @@ -235,18 +235,18 @@ We are now ready to establish the triviality of low-dimensional representations. \begin{proof}[Proof of Theorem~\ref{thm:low-dim-reps-are-trivial}] - Let \(g \ge 1\), \(b \ge 0\) and fix \(\rho : \Mod(S_g^b) \to + Let \(g \ge 1\), \(p \ge 0\) and fix \(\rho : \Mod(S_g^p) \to \GL_n(\mathbb{C})\) with \(n < 2g\). As promised, we proceed by induction on \(g\). The base case \(g = 1\) is again clear from the fact \(n = 1\) and \(\GL_1(\mathbb{C}) = \mathbb{C}^\times\). The case \(g = 2\) was also established in Proposition~\ref{thm:low-dim-reps-are-trivial-base-case}. Now suppose \(g \ge 3\) and every \(m\)-dimensional representation of \(S_{g - - 1}^{b'}\) has Abelian image for \(m < 2(g - 1)\). Let us show \(\rho\) has + 1}^q\) has Abelian image for \(m < 2(g - 1)\). Let us show \(\rho\) has Abelian image. Let \(\alpha_1, \ldots, \alpha_g, \beta_1, \ldots, \beta_g, \gamma_1, \ldots, - \gamma_{g - 1}, \eta_1, \ldots, \eta_{b - 1} \subset S_g^b\) be the curves - from the Lickorish generators of \(\Mod(S_g^b)\), as in + \gamma_{g - 1}, \eta_1, \ldots, \eta_{p-1} \subset S_g^p\) be the curves + from the Lickorish generators of \(\Mod(S_g^p)\), as in Figure~\ref{fig:lickorish-gens}. Once again, let \(L_\alpha = \rho(\tau_\alpha)\) and denote by \(E_{\alpha = \lambda}\) the eigenspace of \(L_\alpha\) associated to \(\lambda \in \mathbb{C}\). Let \(R \cong S_{g - @@ -256,14 +256,14 @@ representations. \begin{figure}[ht] \centering \includegraphics[width=.35\linewidth]{images/lickorish-gens-korkmaz-proof.eps} - \caption{The subsurface $R \subset S_g^b$.} + \caption{The subsurface $R \subset S_g^p$.} \label{fig:korkmaz-proof-subsurface} \end{figure} % TODO: Add more comments on the injectivity of this map? We claim that it suffices to find a \(m\)-dimensional \(\Mod(R)\)-invariant\footnote{Here we view $\Mod(R)$ as a subgroup of - $\Mod(S_g^b)$ via the inclusion homomorphism $\Mod(R) \to \Mod(S_g^b)$ from + $\Mod(S_g^p)$ via the inclusion homomorphism $\Mod(R) \to \Mod(S_g^p)$ from Example~\ref{ex:inclusion-morphism}, which can be shown to be injective in this particular case.} subspace \(W \subset \mathbb{C}^n\) with \(2 \le m \le n - 2\). Indeed, in this case \(m < 2(g - 1)\) and \(\dim @@ -291,9 +291,9 @@ representations. follows from Proposition~\ref{thm:commutator-is-perfect} that \(\rho\) annihilates all of \(\Mod(R)'\) and, in particular, \(\tau_{\alpha_1} \tau_{\beta_1}^{-1} \in \ker \rho\). But recall from - Proposition~\ref{thm:commutator-normal-gen} that \(\Mod(S_g^b)'\) is normally + Proposition~\ref{thm:commutator-normal-gen} that \(\Mod(S_g^p)'\) is normally generated by \(\tau_{\alpha_1} \tau_{\beta_1}^{-1}\), from which we conclude - \(\rho(\Mod(S_g^b)') = 1\), as desired. + \(\rho(\Mod(S_g^p)') = 1\), as desired. As before, we exhaustively analyse all possible Jordan forms of \(L_{\alpha_g}\). First, consider the case where we can find eigenvalues @@ -354,9 +354,9 @@ representations. For case (1), we use the change of coordinates principle: each \(L_{\alpha_i}, L_{\beta_i}, L_{\gamma_i}, L_{\eta_i}\) is conjugate to - \(L_{\alpha_g} = \lambda\), so all Lickorish generators of \(\Mod(S_g^b)\) + \(L_{\alpha_g} = \lambda\), so all Lickorish generators of \(\Mod(S_g^p)\) act on \(\mathbb{C}^n\) as scalar multiplication by \(\lambda\) as well. - Hence \(\rho(\Mod(S_g^b))\) is cyclic and thus Abelian. In case (2), \(W = + Hence \(\rho(\Mod(S_g^p))\) is cyclic and thus Abelian. In case (2), \(W = \ker (L_{\alpha_g} - \lambda)^2\) is a \(2\)-dimensional \(\Mod(R)\)-invariant subspace. @@ -372,7 +372,7 @@ representations. E_{\beta_g = \lambda}\). In this situation, as in the proof of Proposition~\ref{thm:low-dim-reps-are-trivial-base-case} it follows from the change of coordinates principle that there are \(f_i, g_i, h_i \in - \Mod(S_g^b)\) with + \Mod(S_g^p)\) with \begin{align*} f_i \tau_{\alpha_g} f_i^{-1} & = \tau_{\alpha_i} & @@ -391,7 +391,7 @@ representations. E_{\alpha_1 = \lambda} = \cdots = E_{\alpha_g = \lambda} = E_{\beta_1 = \lambda} = \cdots = E_{\beta_g = \lambda} = E_{\gamma_1 = \lambda} = \cdots = E_{\gamma_{g - 1} = \lambda} - = E_{\eta_1 = \lambda} = \cdots = E_{\eta_{b - 1} = \lambda}. + = E_{\eta_1 = \lambda} = \cdots = E_{\eta_{p-1} = \lambda}. \] In particular, we can find a basis for \(\mathbb{C}^n\) with respect to which @@ -405,21 +405,21 @@ representations. 0 & 0 & \cdots & 0 & * \end{pmatrix}. \] - Since the group of upper triangular matrices is solvable and \(\Mod(S_g^b)\) - is perfect, it follows that \(\rho(\Mod(S_g^b))\) is trivial. This concludes - the proof \(\rho(\Mod(S_g^b))\) is Abelian. - - To see that \(\rho(\Mod(S_g^b)) = 1\) for \(g \ge 3\) we note that, since - \(\rho(\Mod(S_g^b))\) is Abelian, \(\rho\) factors though the Abelinization - map \(\Mod(S_g^b) \to \Mod(S_g^b)^\ab = \mfrac{\Mod(S_g^b)}{[\Mod(S_g^b), - \Mod(S_g^b)]}\). Now recall from Proposition~\ref{thm:trivial-abelianization} - that \(\Mod(S_g^b)^\ab = 0\) for \(g \ge 3\). In other words, \(\rho\) + Since the group of upper triangular matrices is solvable and \(\Mod(S_g^p)\) + is perfect, it follows that \(\rho(\Mod(S_g^p))\) is trivial. This concludes + the proof \(\rho(\Mod(S_g^p))\) is Abelian. + + To see that \(\rho(\Mod(S_g^p)) = 1\) for \(g \ge 3\) we note that, since + \(\rho(\Mod(S_g^p))\) is Abelian, \(\rho\) factors though the Abelinization + map \(\Mod(S_g^p) \to \Mod(S_g^p)^\ab = \mfrac{\Mod(S_g^p)}{[\Mod(S_g^p), + \Mod(S_g^p)]}\). Now recall from Proposition~\ref{thm:trivial-abelianization} + that \(\Mod(S_g^p)^\ab = 0\) for \(g \ge 3\). In other words, \(\rho\) factors though the homomorphism \(1 \to \GL_n(\mathbb{C})\). We are done. \end{proof} Having established the triviality of the low-dimensional representations \(\rho -: \Mod(S_g^b) \to \GL_n(\mathbb{C})\), all that remains for us is to understand -the \(2g\)-dimensional reprensentations of \(\Mod(S_g^b)\). We certainly know a +: \Mod(S_g^p) \to \GL_n(\mathbb{C})\), all that remains for us is to understand +the \(2g\)-dimensional reprensentations of \(\Mod(S_g^p)\). We certainly know a nontrivial example of such, namely the symplectic representation \(\psi : \Mod(S_g) \to \operatorname{Sp}_{2g}(\mathbb{Z})\) from Example~\ref{ex:symplectic-rep}. Surprinsgly, this turns out to be @@ -427,13 +427,13 @@ Example~\ref{ex:symplectic-rep}. Surprinsgly, this turns out to be representation in the compact case. More precisely, \begin{theorem}[Korkmaz]\label{thm:reps-of-dim-2g-are-symplectic} - Let \(g \ge 3\) and \(\rho : \Mod(S_g^b) \to \GL_{2g}(\mathbb{C})\). Then + Let \(g \ge 3\) and \(\rho : \Mod(S_g^p) \to \GL_{2g}(\mathbb{C})\). Then \(\rho\) is either trivial or conjugate to the symplectic - representation\footnote{Here the map $\Mod(S_g^b) \to + representation\footnote{Here the map $\Mod(S_g^p) \to \operatorname{Sp}_{2g}(\mathbb{Z})$ is given by the composition of the - inclusion morphism $\Mod(S_g^b) \to \Mod(S_g)$ with the usual symplect + inclusion morphism $\Mod(S_g^p) \to \Mod(S_g)$ with the usual symplect representation $\psi : \Mod(S_g) \to \operatorname{Sp}_{2g}(\mathbb{Z})$.} - \(\Mod(S_g^b) \to \operatorname{Sp}_{2g}(\mathbb{Z})\) of \(\Mod(S_g^b)\). + \(\Mod(S_g^p) \to \operatorname{Sp}_{2g}(\mathbb{Z})\) of \(\Mod(S_g^p)\). \end{theorem} Unfortunately, the limited scope of these master thesis does not allow us to @@ -483,7 +483,7 @@ to as \emph{the main lemma}. Namely\dots This is proved in \cite[Lemma 7.6]{korkmaz} using the braid relations. Notice that for \(n = g\) and \(m = 2g\) the matrices in Lemma~\ref{thm:main-lemma} coincide with the action of the Lickrish generators \(\tau_{\alpha_1}, \ldots, -\tau_{\alpha_g}, \tau_{\beta_1}, \ldots, \tau_{\beta_g} \in \Mod(S_g^b)\) on +\tau_{\alpha_g}, \tau_{\beta_1}, \ldots, \tau_{\beta_g} \in \Mod(S_g^p)\) on \(H_1(S_g, \mathbb{C}) \cong \mathbb{C}^{2g}\) -- represented in the standard basis \([\alpha_1], \ldots, [\alpha_g], [\beta_1], \ldots, [\beta_g]\) for \(H_1(S_g, \mathbb{C})\). @@ -506,28 +506,28 @@ basis \([\alpha_1], \ldots, [\alpha_g], [\beta_1], \ldots, [\beta_g]\) for \right) \end{align*} -Hence by embeding \(B_3^g\) in \(\Mod(S_g^b)\) via +Hence by embeding \(B_3^g\) in \(\Mod(S_g^p)\) via \begin{align*} - B_3^g & \to \Mod(S_g^b) \\ + B_3^g & \to \Mod(S_g^p) \\ a_i & \mapsto \tau_{\alpha_i} \\ b_i & \mapsto \tau_{\beta_i} \end{align*} -we can see that any \(\rho : \Mod(S_g^b) \to \GL_{2g}(\mathbb{C})\) in a +we can see that any \(\rho : \Mod(S_g^p) \to \GL_{2g}(\mathbb{C})\) in a certain class of representation satisfying some technical conditions must be -conjugate to the symplectic representation \(\Mod(S_g^b) \to +conjugate to the symplectic representation \(\Mod(S_g^p) \to \operatorname{Sp}_{2g}(\mathbb{Z})\) when restricted to \(B_3^g\). Korkmaz then goes on to show that such technical conditions are met for any -nontrivial \(\rho : \Mod(S_g^b) \to \GL_{2g}(\mathbb{C})\). Furthermore, +nontrivial \(\rho : \Mod(S_g^p) \to \GL_{2g}(\mathbb{C})\). Furthermore, Korkmaz also argues that we can find a basis for \(\mathbb{C}^{2g}\) with respect to which the matrices of \(\rho(\tau_{\gamma_1}), \ldots, \rho(\tau_{\gamma_{g - 1}}), \rho(\tau_{\eta_1}), \ldots, -\rho(\tau_{\eta_{b-1}})\) also agrees with the action of \(\Mod(S_g^b)\) on +\rho(\tau_{\eta_{p-1}})\) also agrees with the action of \(\Mod(S_g^p)\) on \(H_1(S_g, \mathbb{C})\), concluding the classification of \(2g\)-dimensional representations. % TODO: Add some final comments about how the rest of the landscape of % representations is generally unknown and how there is a lot to study in here Recently, Kasahara \cite{kasahara} also classified the \((2g+1)\)-dimensional -representations of \(\Mod(S_g^b)\) for \(g \ge 7\) in terms of certain twisted +representations of \(\Mod(S_g^p)\) for \(g \ge 7\) in terms of certain twisted \(1\)-cohomology groups.
diff --git a/sections/twists.tex b/sections/twists.tex @@ -183,9 +183,9 @@ too. A perhaps less obvious fact about Dehn twists is\dots \begin{theorem}\label{thm:mcg-is-fg} - Let \(S_{g, r}^b\) be the orientable surface of genus \(g \ge 1\) with \(r\) + Let \(S_{g, r}^p\) be the orientable surface of genus \(g \ge 1\) with \(r\) punctures and \(b\) boundary components. Then the pure mapping class group - \(\PMod(S_{g, r}^b)\) is generated by finitely many Dehn twists about + \(\PMod(S_{g, r}^p)\) is generated by finitely many Dehn twists about nonseparating curves or boundary components. \end{theorem} @@ -198,9 +198,9 @@ curves}. \section{The Birman Exact Sequence} Having the proof of Theorem~\ref{thm:mcg-is-fg} in mind, it is interesting to -consider the relationship between the mapping class group of \(S_{g, r}^b\) and -that of \(S_{g, r+1}^b = S_{g, r}^b \setminus \{ x \}\) for some \(x\) in the -interior \((S_{g, r}^b)\degree\) of \(S_{g, r}^b\). Indeed, this will later +consider the relationship between the mapping class group of \(S_{g, r}^p\) and +that of \(S_{g, r+1}^p = S_{g, r}^p \setminus \{ x \}\) for some \(x\) in the +interior \((S_{g, r}^p)\degree\) of \(S_{g, r}^p\). Indeed, this will later allow us to establish the induction on the number of punctures \(r\). Given an orientable surface \(S\) and \(x_1, \ldots, x_n \in S\degree\), @@ -289,7 +289,7 @@ show\dots \section{The Modified Graph of Curves} Having established Theorem~\ref{thm:birman-exact-seq}, we now need to adress -the induction step in the genus \(g\) of \(S_{g, r}^b\). Our strategy is to +the induction step in the genus \(g\) of \(S_{g, r}^p\). Our strategy is to apply the following lemma from geomtric group theory. \begin{lemma}\label{thm:ggt-lemma} @@ -301,7 +301,7 @@ apply the following lemma from geomtric group theory. \(G\) is generated by \(G_v\) and \(g\). \end{lemma} -We are interested, of course, in the group \(G = \PMod(S_{g, r}^b)\). As for +We are interested, of course, in the group \(G = \PMod(S_{g, r}^p)\). As for the graph \(\Gamma\), we consider\dots \begin{definition} @@ -317,9 +317,9 @@ the graph \(\Gamma\), we consider\dots \end{definition} It is clear from Lemma~\ref{thm:change-of-coordinates} that the actions of -\(\Mod(S_{g, r}^b)\) on \(V(\hat{\mathcal{N}}(S_{g, r}^b))\) and \(\{([\alpha], -[\beta]) \in V(\hat{\mathcal{N}}(S_{g, r}^b))^2 : \#(\alpha \cap \beta) = 1 -\}\) are both transitive. But why should \(\hat{\mathcal{N}}(S_{g, r}^b)\) be +\(\Mod(S_{g, r}^p)\) on \(V(\hat{\mathcal{N}}(S_{g, r}^p))\) and \(\{([\alpha], +[\beta]) \in V(\hat{\mathcal{N}}(S_{g, r}^p))^2 : \#(\alpha \cap \beta) = 1 +\}\) are both transitive. But why should \(\hat{\mathcal{N}}(S_{g, r}^p)\) be connected? Historically, the modified graph of nonseparating curves first arised as a @@ -361,30 +361,30 @@ Corollary~\ref{thm:mofied-graph-is-connected}. We are now ready to show Theorem~\ref{thm:mcg-is-fg}. \begin{proof}[Proof of Theorem~\ref{thm:mcg-is-fg}] - Let \(S_{g, r}^b\) be the orientable surface of genus \(g \ge 1\) with \(r\) + Let \(S_{g, r}^p\) be the orientable surface of genus \(g \ge 1\) with \(r\) punctures and \(b\) boundary components. We want to establish that - \(\PMod(S_{g, r}^b)\) is genetery by a finite number of Dehn twists about + \(\PMod(S_{g, r}^p)\) is genetery by a finite number of Dehn twists about nonseparating simple closed curves or boundary components. - First, observe that if \(b \ge 1\) and \(\partial S_{g, r}^b = \delta_1 \cup - \cdots \cup \delta_b\) then, by recursively applying the capping exact + First, observe that if \(p \ge 1\) and \(\partial S_{g, r}^p = \delta_1 \cup + \cdots \cup \delta_p\) then, by recursively applying the capping exact sequence \begin{center} \begin{tikzcd} 1 \rar & \langle \tau_{\delta_1} \rangle \rar & - \PMod(S_{g, r}^b) \rar{\operatorname{cap}} & - \PMod(S_{g, r}^b \cup_{\delta_1} (\mathbb{D}^2 \setminus \{0\})) \rar & + \PMod(S_{g, r}^p) \rar{\operatorname{cap}} & + \PMod(S_{g, r}^p \cup_{\delta_1} (\mathbb{D}^2 \setminus \{0\})) \rar & 1 \end{tikzcd} \end{center} from Example~\ref{ex:capping-seq}, it suffices to show that \(S_{g, n}\) is finitely generated by twists about nonseparating simple closed curves. - Indeed, if \(\PMod(S_{g, r}^b \cup_{\delta_1} (\mathbb{D}^2 \setminus \{0\}))\) + Indeed, if \(\PMod(S_{g, r}^p \cup_{\delta_1} (\mathbb{D}^2 \setminus \{0\}))\) is finitely generated by twists about nonseparing curves or boundary - components, then we may lift the generators of \(\PMod(S_{g, r}^b + components, then we may lift the generators of \(\PMod(S_{g, r}^p \cup_{\delta_1} (\mathbb{D}^2 \setminus \{0\}))\) to Dehn twists about the - corresponding curves in \(S_{g, r}^b\) and add \(\tau_{\delta_1}\) to the + corresponding curves in \(S_{g, r}^p\) and add \(\tau_{\delta_1}\) to the generating set. It thus suffices to consider the boudaryless case \(S_{g, r}\). As promised, @@ -498,18 +498,18 @@ Theorem~\ref{thm:mcg-is-fg}. There are many possible improvements to this last result. For instance, in \cite[Section~4.4]{farb-margalit} Farb-Margalit exhibit an explicit set of -generators of \(\Mod(S_g^b)\) by addapting the induction steps in the proof of +generators of \(\Mod(S_g^p)\) by addapting the induction steps in the proof of Theorem~\ref{thm:mcg-is-fg}. These are known as the \emph{Lickorish generators}. \begin{theorem}[Lickorish generators]\label{thm:lickorish-gens} - If \(g \ge 1\) then \(\Mod(S_g^b)\) is generated by the Dehn twists about the + If \(g \ge 1\) then \(\Mod(S_g^p)\) is generated by the Dehn twists about the curves \(\alpha_1, \ldots, \alpha_g, \beta_1, \ldots, \beta_g, \gamma_1, - \ldots, \gamma_{g - 1}, \eta_1, \ldots, \eta_{b - 1}\) as in + \ldots, \gamma_{g - 1}, \eta_1, \ldots, \eta_{p-1}\) as in Figure~\ref{fig:lickorish-gens} \end{theorem} -In the boundaryless case \(b = 0\), we can write \(\tau_{\mu_3}, \ldots, +In the boundaryless case \(p = 0\), we can write \(\tau_{\mu_3}, \ldots, \tau_{\mu_g} \in \Mod(S_g)\) as products of the twists about the remaining curves, from which we get the so called \emph{Humphreys generators}. @@ -522,7 +522,7 @@ curves, from which we get the so called \emph{Humphreys generators}. \begin{minipage}[b]{.45\linewidth} \centering \includegraphics[width=\linewidth]{images/lickorish-gens.eps} - \captionof{figure}{The curves from Lickorish generators of $\Mod(S_g^b)$.} + \captionof{figure}{The curves from Lickorish generators of $\Mod(S_g^p)$.} \label{fig:lickorish-gens} \end{minipage} \hspace{.5cm} %