diff --git a/sections/complete-reducibility.tex b/sections/complete-reducibility.tex
@@ -1,13 +1,14 @@
\chapter{Semisimplicity \& Complete Reducibility}
+% TODO: Automate the "47 pages" thing
Having hopefully established in the previous chapter that Lie algebras and
their representations are indeed useful, we are now faced with the Herculean
-task of trying to understand them. We have seen that representations are a
-remarkably effective way to derive information about groups -- and therefore
-algebras -- but the question remains: how to we go about classifying the
-representations of a given Lie algebra? This is a question that have sparked an
-entire field of research, and we cannot hope to provide a comprehensive answer
-the 47 pages we have left. Nevertheless, we can work on particular cases.
+task of trying to understand them. We have seen that representations can be
+used to derive geometric information about groups, but the question remains:
+how to we go about classifying the representations of a given Lie algebra? This
+is a question that have sparked an entire field of research, and we cannot hope
+to provide a comprehensive answer the 47 pages we have left. Nevertheless, we
+can work on particular cases.
For instance, one can readily check that a representation \(V\) of the
\(n\)-dimensional Abelian Lie algebra \(K^n\) is nothing more than a choice of
@@ -16,14 +17,13 @@ canonical basis elements \(e_1, \ldots, e_n \in K^n\). In other words,
classifying the representations of Abelian algebras is a trivial affair.
Instead, we focus on the the finite-dimensional representations of a
finite-dimensional Lie algebra \(\mathfrak{g}\) over an algebraically closed
-field of characteristic \(0\). But why are the representations semisimple
+field \(K\) of characteristic \(0\). But why are the representations semisimple
algebras simpler -- or perhaps \emph{semisimpler} -- to understand than those
of any old Lie algebra?
-We will come back to this question in a moment, but for now we simply note
-that, when solving a classification problem, it is often profitable to break
-down our structure is smaller peaces. This leads us to the following
-definitions.
+We will get back to this question in a moment, but for now we simply note that,
+when solving a classification problem, it is often profitable to break down our
+structure is smaller peaces. This leads us to the following definitions.
\begin{definition}
A representation of \(\mathfrak{g}\) is called \emph{indecomposable} if it is
@@ -32,7 +32,7 @@ definitions.
\begin{definition}
A representation of \(\mathfrak{g}\) is called \emph{irreducible} if it has
- no nonzero subrepresentations.
+ no nonzero proper subrepresentations.
\end{definition}
\begin{example}
@@ -54,13 +54,13 @@ algebra is to classify the indecomposable representations. This is because\dots
Hence finding the indecomposable representations suffices to find \emph{all}
finite-dimensional representations: they are the direct sum of indecomposable
representations. The existence of the decomposition should be clear from the
-definitions. Indeed, if \(V\) is representation of \(\mathfrak{g}\) a simple
-argument via induction in \(\dim V\) suffices to prove the existence: if \(V\)
-is indecomposable then there is nothing to prove, and if \(V\) is not
-indecomposable then \(V = W \oplus U\) for some \(W, U \subsetneq V\) nonzero
-subrepresentations, so that their dimensions are both strictly smaller than
-\(\dim V\) and the existence follows from the induction hypothesis. For a proof
-of uniqueness please refer to \cite{etingof}.
+definitions. Indeed, if \(V\) is a finite-dimensional representation of
+\(\mathfrak{g}\) a simple argument via induction in \(\dim V\) suffices to
+prove the existence: if \(V\) is indecomposable then there is nothing to prove,
+and if \(V\) is not indecomposable then \(V = W \oplus U\) for some \(W, U
+\subsetneq V\) nonzero subrepresentations, so that their dimensions are both
+strictly smaller than \(\dim V\) and the existence follows from the induction
+hypothesis. For a proof of uniqueness please refer to \cite{etingof}.
Finding the indecomposable representations of an arbitrary Lie algebra,
however, turns out to be a bit of a circular problem: the indecomposable
@@ -119,49 +119,49 @@ clear things up.
\end{proposition}
\begin{proof}
- We begin by \(\textbf{(i)} \Rightarrow \textbf{(ii)}\). Let
+ We begin by \(\textbf{(i)} \implies \textbf{(ii)}\). Let
\begin{center}
\begin{tikzcd}
- 0 \arrow{r} &
- W \arrow{r}{f} &
- V \arrow{r}{g} &
- U \arrow{r} &
+ 0 \arrow{r} &
+ W \arrow{r}{i} &
+ V \arrow{r}{\pi} &
+ U \arrow{r} &
0
\end{tikzcd}
\end{center}
be an exact sequence of representations of \(\mathfrak{g}\). We can suppose
without any loss of generality that \(W \subset V\) is a subrepresentation
- and \(f\) is the usual inclusion, for if this is not the case there is an
+ and \(i\) is its inclusion in \(V\), for if this is not the case there is an
isomorphism of sequences
\begin{center}
\begin{tikzcd}
- 0 \arrow{r} &
- W \arrow{r}{f} \arrow[swap]{d}{f} &
- V \arrow{r}{g} \arrow[Rightarrow, no head]{d} &
- U \arrow{r} \arrow[Rightarrow, no head]{d} &
- 0 \\
- 0 \arrow{r} &
- f(W) \arrow{r} &
- V \arrow[swap]{r}{g} &
- U \arrow{r} &
+ 0 \arrow{r} &
+ W \arrow{r}{i} \arrow[swap]{d}{i} &
+ V \arrow{r}{\pi} \arrow[Rightarrow, no head]{d} &
+ U \arrow{r} \arrow[Rightarrow, no head]{d} &
+ 0 \\
+ 0 \arrow{r} &
+ i(W) \arrow{r} &
+ V \arrow[swap]{r}{\pi} &
+ U \arrow{r} &
0
\end{tikzcd}
\end{center}
It then follows from \textbf{(i)} that there exists a subrepresentation \(U'
- \subset V\) such that \(V = W \oplus U'\). Finally, the projection \(\pi : V
+ \subset V\) such that \(V = W \oplus U'\). Finally, the projection \(T : V
\to W\) is an intertwiner satisfying
\begin{center}
\begin{tikzcd}
- 0 \arrow{r} &
- W \arrow{r}{f} &
- V \arrow{r}{g} \arrow[bend left=30]{l}{\pi} &
- U \arrow{r} &
+ 0 \arrow{r} &
+ W \arrow{r}{i} &
+ V \arrow{r}{\pi} \arrow[bend left=30]{l}{T} &
+ U \arrow{r} &
0
\end{tikzcd}
\end{center}
- Next is \(\textbf{(ii)} \Rightarrow \textbf{(iii)}\). If \(V\) is an
+ Next is \(\textbf{(ii)} \implies \textbf{(iii)}\). If \(V\) is an
indecomposable \(\mathfrak{g}\)-module and \(W \subset V\) is a
subrepresentation, we have an exact sequence
\begin{center}
@@ -178,11 +178,11 @@ clear things up.
Since our sequence splits, we must have \(V \cong W \oplus \mfrac{V}{W}\).
But \(V\) is indecomposable, so that either \(W = V\) or \(W = 0\). Since
this holds for all \(W \subset V\), \(V\) is irreducible. For
- \(\textbf{(iii)} \Rightarrow \textbf{(iv)}\) it suffices to apply
+ \(\textbf{(iii)} \implies \textbf{(iv)}\) it suffices to apply
theorem~\ref{thm:krull-schmidt}.
- Finally, for \(\textbf{(iv)} \Rightarrow \textbf{(i)}\), if we assume
- \(\textbf{(iii)}\) and let \(V\) be a representation of \(\mathfrak{g}\) with
+ Finally, for \(\textbf{(iv)} \implies \textbf{(i)}\), if we assume
+ \(\textbf{(iv)}\) and let \(V\) be a representation of \(\mathfrak{g}\) with
decomposition into irreducible subrepresentations
\[
V = \bigoplus_i V_i
@@ -457,7 +457,7 @@ basic}. In fact, all we need to know is\dots
a more modern account using derived categories.
\end{note}
-We are particular interested in the case where \(S = K\) is the trivial
+We are particularly interested in the case where \(S = K\) is the trivial
representation of \(\mathfrak{g}\). Namely, we may define\dots
\begin{definition}